Algebraic Word Problems and Number Properties Notes for XAT: Concepts, Formulas, Worked Examples & Practice

    Algebraic Word Problems and Number Properties notes for XAT: 28 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questions.

    Chapter Roadmap: Algebraic Word Problems and Number Properties

    Chapter Roadmap

    Step 1: Number Properties & Algebraic Expressions

    Master parity, divisibility, prime constraints, symmetric identities, and the behavior of exponents in integer domains.

    Step 2: Algebraic Word Problems & Data Sufficiency

    Translate real-world scenarios into equations, optimize variables, and rigorously test if given statements provide a unique solution.

    Topic Hero: Number Properties & Algebraic Expressions

    The Core Intuition

    Algebra in competitive exams is about understanding the behavior of numbers and manipulating expressions to reveal hidden constraints.

    The Golden Rule of Domains

    Integers? Look for factor pairs and divisibility.
    Primes? Look for restricted factorizations.
    Positive? Eliminate negative roots and zero.
    First-Principles Clarity:
    Constraints are not obstacles; they are the primary filters that narrow down infinite real solutions to a single integer answer.

    Concept: Exponents and Perfect Powers

    The Perfect Power Rule

    For an expression composed of prime bases to be a perfect -th power, the exponent of every prime factor must be a multiple of .

    Example: If is a positive integer, then:
    1. must be a multiple of 3.
    2. must be a multiple of 3.
    3. Both and (otherwise, the result is a fraction).
    Key Takeaway:
    Perfect integer powers require non-negative exponents that are perfectly divisible by the root index.

    Concept: Symmetric Expressions and Reciprocals

    The Reciprocal Shortcut

    When given the sum of -th powers and the sum of their reciprocals, you can find the product of the variables directly.

    Derivation:
    Given: and
    Exam Application:
    Use this to bypass finding and individually when asked for .

    Algebraic Word Problems and Number Properties: Solved Questions with Step-by-Step Explanations (2 Problems)

    Question 1 · Quantitative Aptitude and Data Interpretation (QA & DI) NAT

    Let be a positive integer such that is a perfect cube. What is the sum of all possible values of ?

    Correct Answer:

    0

    Step-by-Step Solution

    Key idea: This is a perfect power bounding problem. For large , the expression lies strictly between consecutive cubes, so only small need checking. Modular arithmetic eliminates remaining candidates.

    Step 1: Compare with nearby cubes. Note .

    Our expression: .

    Difference: .

    For , .

    Step 2: Compare with . Clearly for .

    So for , . Thus cannot be a perfect cube for .

    Step 3: Check : , not a cube.

    Step 4: No positive integer satisfies the condition. Sum of all possible values is 0.

    Step 5: Verify no edge cases missed. For (not positive), , not cube. Negative excluded by problem.

    Answer: 0

    Question 2 · Quantitative Aptitude and Data Interpretation (QA & DI) MCQ

    Let be the smallest positive integer that has exactly three distinct prime factors and exactly 24 positive divisors. A rectangle has integer side lengths and such that its area is numerically equal to times its semi-perimeter. How many unordered pairs of side lengths exist such that ?

    1. A.

      2

    2. B.

      4

    3. C.

      8

    4. D.

      12

    Correct Answer:

    B

    Step-by-Step Solution

    Key idea: This is a Simon's Favorite Factoring Trick problem combined with divisor counting and coprimality. The geometric condition translates to a Diophantine equation, which we then factor.

    Step 1: Find . We need the smallest integer with 3 distinct prime factors and 24 divisors.

    Let . The number of divisors is .

    To minimize , assign the largest exponents to the smallest primes (2, 3, 5).

    The optimal factorization of 24 into three integers is .

    Thus, .

    Step 2: Translate the geometric condition. Area , semi-perimeter .

    .

    Add to both sides: .

    Step 3: Apply the coprimality constraint. Let and . We need and .

    Since , .

    For and to be coprime, they cannot share any prime factors. Thus, each prime power () must be assigned entirely to either or .

    Step 4: Count the pairs. There are 3 distinct prime powers, so there are ordered pairs .

    Since and , . Thus, the number of unordered pairs is .

    Each valid gives a unique valid since .

    Answer: 4

    More notes in this unit

    chapter
    Algebraic Word Problems and Number Properties Notes for XAT: Concepts, Formulas, Worked Examples & Practice

    Algebraic Word Problems and Number Properties notes for XAT: 28 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questi

    A question from this chapter

    Question 1

    Let be a positive integer such that is a perfect cube. What is the sum of all possible values of ?

    Question 2

    Let be the smallest positive integer that has exactly three distinct prime factors and exactly 24 positive divisors. A rectangle has integer side lengths and such that its area is numerically equal to times its semi-perimeter. How many unordered pairs of side lengths exist such that ?

    Free preview ends here

    Login to view the complete notes

    Creating an account is free. You get the rest of this chapter, step-by-step solutions, and a study plan built around the topics you are actually weak at.

    Why MastersUp

    Personalised first. High quality throughout.

    Most platforms hand everyone the same content. Here the content moves with your performance, topic by topic.

    Built around you, not around a syllabus PDF

    Every answer you give moves your topic-level intelligence rate. The next question, the next revision card and tomorrow's plan all change with it.

    Revision that hits your weak spots

    We only revise topics you have actually attempted and are still below the safe bar on — never the same chapter on repeat.

    Questions calibrated to the real exam

    Each question carries a measured toughness. You are served a rung above your current level, so practice keeps stretching you.

    Notes written for recall, not for volume

    Full lesson cards for first study, curated short-note cards for the last mile — with derivations, traps and exam patterns marked.

    One place for everything

    Notes, chapter practice, previous-year questions, test series and full-length papers — all feeding one picture of your preparation.

    Honest progress

    No vanity streaks. Progress here means chapters mastered and accuracy that held up on harder questions.

    Unlock the whole course

    Full notes and short notes, the complete question bank with worked solutions, mock tests, full-length papers, and an adaptive plan that rebuilds itself as you improve.