Circles, Chords, Tangents and Incircles Short Notes for CAT: Concepts, Formulas, Worked Examples & Practice

    Circles, Chords, Tangents and Incircles short notes for CAT: 47 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questions.

    The Master Move: Drop a Perpendicular from Centre

    O M A half chord
    Core theorem

    Centre perpendicular to chord bisects the chord

    For chord , if , then .

    radius squared equals distance from centre squared plus half-chord squared.

    Chord Length from Radius and Distance

    Chord length formula

    Radius , distance of chord from centre .

    Half chord
    Full chord
    Exam translation: distance from centre increases chord becomes shorter.

    Equal Chords, Equal Distances

    Same circle comparison rule

    Equal chords are equally distant from the centre.
    Equal distances produce equal chords.
    Larger distance produces a smaller chord.
    Use this mainly when two chords are parallel or when their distances from the centre are compared.

    Chord Length from Central Angle

    Central angle gives chord

    If chord subtends angle at centre :

    Most useful for angles like , , .

    θ O A B

    Circles, Chords, Tangents and Incircles: Solved Questions with Step-by-Step Explanations (2 Problems)

    Question 1 · Quantitative Ability MCQ

    Three identical circles of radius cm touch each other externally. A smaller circle is placed in the central gap so that it touches all three circles externally. What is its radius, in cm?

    1. A.

      2√3 - 3

    2. B.

      3 - 2√3

    3. C.

      2√3 + 3

    4. D.

      6 - 2√3

    Correct Answer:

    A

    Step-by-Step Solution

    Key idea: inner circle in the symmetric gap between three equal touching circles.

    Step 1: Centres of the three given circles form an equilateral triangle of side

    Step 2: The gap circle centre is the triangle centre. Distance from triangle centre to a vertex is the circumradius:

    Step 3: If the small radius is , external touch gives

    Step 4: Solve:

    Answer: Option A.

    Trap: using subtraction here belongs to the outer enclosing circle case. The inner gap circle touches externally, so radii add.

    Question 2 · Quantitative Ability MCQ

    In a circle of radius cm, two parallel chords have lengths cm and cm. The chords may be placed on either side of the centre. What is the greatest possible area, in square cm, of the trapezium formed by joining their corresponding endpoints?

    1. A.

      28

    2. B.

      98

    3. C.

      280

    4. D.

      196

    Correct Answer:

    D

    Step-by-Step Solution

    Key idea: this is a parallel-chords trapezium question with a maximisation layer. The parallel sides are the chords, so the area is

    Step 1: Find the distance of each chord from the centre. For chord length and radius ,

    For the cm chord:

    For the cm chord:

    Step 2: Maximise the distance between the chords. If they are on the same side, separation is . If they are on opposite sides, separation is . The greatest possible height is therefore .

    Step 3: Compute the maximum area.

    Answer: Option D.

    Trap check: using the same-side separation gives the minimum area, while using the diameter as height ignores the actual chord positions.

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    Circles, Chords, Tangents and Incircles Short Notes for CAT: Concepts, Formulas, Worked Examples & Practice

    Circles, Chords, Tangents and Incircles short notes for CAT: 47 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questi

    A question from this chapter

    Question 1

    Three identical circles of radius cm touch each other externally. A smaller circle is placed in the central gap so that it touches all three circles externally. What is its radius, in cm?

    Question 2

    In a circle of radius cm, two parallel chords have lengths cm and cm. The chords may be placed on either side of the centre. What is the greatest possible area, in square cm, of the trapezium formed by joining their corresponding endpoints?

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