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    Orthogonal, Projection and Special Matrices Notes for GATE DA

    Orthogonal, Projection and Special Matrices notes for GATE DA: 18 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice ques

    orthogonal projection and special matrices notes

    Chapter Roadmap: Orthogonal, Projection and Special Matrices

    Chapter Roadmap

    Welcome to the geometry of linear transformations. This chapter bridges the gap between abstract matrix algebra and visual geometric intuition.

    Your Learning Journey

    1. Projection Matrices and Quadratic Forms

    Classifying surfaces, Rayleigh quotient, centering matrix. High Weightage

    2. Orthogonal and Involutory Matrices

    Length-preserving transformations, rotations, own inverses. Moderate Weightage

    By the end of this chapter, you will:

    • Instantly classify the shape of any quadratic form using eigenvalues.
    • Recognize projection matrices and deduce their eigenvalues without calculation.
    • Solve constrained optimization problems in seconds.

    The Geometry of Quadratic Forms

    The Geometry of Quadratic Forms

    A quadratic form is a scalar-valued polynomial where every term has a degree of exactly two.

    For a column vector and an matrix , the quadratic form is written as:

    Geometric Intuition

    If you set for some constant , you get a geometric surface:

    • In 2D: Conic sections (ellipses, hyperbolas, parabolas).
    • In 3D: Quadric surfaces (ellipsoids, hyperboloids).

    The matrix acts as the "DNA" of this surface, dictating its orientation, stretching, and curvature.

    The Symmetric Matrix Representation

    The Symmetric Matrix Representation

    Every quadratic form can be represented by a unique symmetric matrix.

    If you are given a non-symmetric matrix , the quadratic form is exactly equal to , where is the symmetrized version of :

    Why does this work?

    Because is a scalar, it equals its own transpose:

    Averaging the two gives the symmetric equivalent.

    Golden Rule: Always symmetrize the matrix before analyzing eigenvalues or definiteness.

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    Question 1
    Level 1: Warm-up

    For the centering matrix , what is the value of ?

    Question 2
    Level 1: Warm-up

    Let be a symmetric matrix with eigenvalues and . What is the minimum value of subject to ?

    Question 3
    Level 1: Warm-up

    Let be a real symmetric matrix such that the eigenvalues of are and . What is the minimum value of subject to ?

    Question 4
    Level 1: Warm-up

    Let be a real symmetric matrix such that . If the trace of is , what is the minimum value of subject to ?

    Question 5
    Level 1: Warm-up

    If the eigenvalues of a symmetric matrix are and , the quadratic form is classified as:

    Question 6
    Level 1: Warm-up

    A matrix is an orthogonal projection matrix. If the rank of is , what is the sum of its eigenvalues?

    Question 7
    Level 1: Warm-up

    Consider the following statements:

    Assertion (A): The quadratic form with is positive definite.

    Reason (R): The eigenvalues of are both positive.

    Which of the following is correct?

    Question 8
    Level 1: Warm-up
    Match the following matrix properties with their correct values for a centering matrix .
    List I: 1. Trace of 2. Determinant of 3. Eigenvalues of
    List II: P. and (with multiplicities and ) Q. R.
    Question 9
    Level 1: Warm-up

    Let . If , for how many values of is the expression positive definite for all ?

    Question 10
    Level 1: Warm-up

    Consider the following statements:

    Assertion (A): The expression with is positive definite.

    Reason (R): The diagonal elements of are positive.

    Which of the following is correct?

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    Orthogonal, Projection and Special Matrices Notes for GATE DA

    Orthogonal, Projection and Special Matrices notes for GATE DA: 18 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questions.

    Chapter Roadmap: Orthogonal, Projection and Special Matrices

    Chapter Roadmap

    Welcome to the geometry of linear transformations. This chapter bridges the gap between abstract matrix algebra and visual geometric intuition.

    Your Learning Journey

    1. Projection Matrices and Quadratic Forms

    Classifying surfaces, Rayleigh quotient, centering matrix. High Weightage

    2. Orthogonal and Involutory Matrices

    Length-preserving transformations, rotations, own inverses. Moderate Weightage

    By the end of this chapter, you will:

    • Instantly classify the shape of any quadratic form using eigenvalues.
    • Recognize projection matrices and deduce their eigenvalues without calculation.
    • Solve constrained optimization problems in seconds.

    The Geometry of Quadratic Forms

    The Geometry of Quadratic Forms

    A quadratic form is a scalar-valued polynomial where every term has a degree of exactly two.

    For a column vector and an matrix , the quadratic form is written as:

    Geometric Intuition

    If you set for some constant , you get a geometric surface:

    • In 2D: Conic sections (ellipses, hyperbolas, parabolas).
    • In 3D: Quadric surfaces (ellipsoids, hyperboloids).

    The matrix acts as the "DNA" of this surface, dictating its orientation, stretching, and curvature.

    The Symmetric Matrix Representation

    The Symmetric Matrix Representation

    Every quadratic form can be represented by a unique symmetric matrix.

    If you are given a non-symmetric matrix , the quadratic form is exactly equal to , where is the symmetrized version of :

    Why does this work?

    Because is a scalar, it equals its own transpose:

    Averaging the two gives the symmetric equivalent.

    Golden Rule: Always symmetrize the matrix before analyzing eigenvalues or definiteness.

    Classifying Quadratic Forms

    Classifying Quadratic Forms

    We classify quadratic forms by observing the sign of for all non-zero vectors . This classification depends entirely on the eigenvalues of the symmetric matrix .

    Classification Eigenvalues of Shape (2D)
    Positive Definite All Ellipse
    Negative Definite All Ellipse (imaginary)
    Positive Semi-Definite All Line or point
    Negative Semi-Definite All Line or point
    Indefinite Mixed signs () Hyperbola
    Exam Shortcut: To check definiteness, just find the eigenvalues of the symmetrized matrix and check their signs.

    Orthogonal, Projection and Special Matrices: Solved Questions with Step-by-Step Explanations (10 Problems)

    Question 1 · Linear Algebra NAT

    For the centering matrix , what is the value of ?

    Correct Answer:

    0

    Step-by-Step Solution

    Key idea: This is a direct substitution question testing the action of the centering matrix on the all-ones vector.

    Step 1: Write down the expression for :

    Step 2: Distribute the vector :

    Step 3: Simplify the terms:

    • .
    • is the dot product of the all-ones vector with itself, which equals (the sum of ones).

    Step 4: Substitute back:

    Step 5: The result is the zero vector. In NAT format asking for "the value" or implying a magnitude/component context where 0 is the unique numeric answer, the answer is 0.

    Answer: 0

    Question 2 · Linear Algebra MCQ

    Let be a symmetric matrix with eigenvalues and . What is the minimum value of subject to ?

    1. A.

      3

    2. B.

      5

    3. C.

      9

    4. D.

      15

    Correct Answer:

    A

    Step-by-Step Solution

    Key idea: The minimum value of a quadratic form on the unit sphere is the smallest eigenvalue of .

    Step 1: The matrix is symmetric with eigenvalues and .

    Step 2: By the Rayleigh quotient theorem, the minimum value is .

    Step 3: The smallest eigenvalue is .

    Answer: 3

    Question 3 · Linear Algebra MCQ

    Let be a real symmetric matrix such that the eigenvalues of are and . What is the minimum value of subject to ?

    1. A.

      -9

    2. B.

      -3

    3. C.

      1

    4. D.

      3

    Correct Answer:

    B

    Step-by-Step Solution

    Key idea: The minimum value of a quadratic form on the unit sphere is the smallest eigenvalue of the symmetric matrix.

    Step 1: If the eigenvalues of are , then the eigenvalues of must be .

    Step 2: Since is a real symmetric matrix, its eigenvalues are real. The possible sets of eigenvalues for are formed by choosing one sign for each magnitude.

    Step 3: To find the absolute minimum possible value of the quadratic form, we want the most negative eigenvalue possible for .

    Step 4: The most negative choice is . Thus, the minimum value of is .

    Answer: -3

    Question 4 · Linear Algebra MCQ

    Let be a real symmetric matrix such that . If the trace of is , what is the minimum value of subject to ?

    1. A.

      2

    2. B.

      5

    3. C.

      12

    4. D.

      10

    Correct Answer:

    A

    Step-by-Step Solution

    Key idea: The minimum value of a quadratic form on the unit sphere is the smallest eigenvalue of the symmetric matrix.

    Step 1: The matrix equation implies that the minimal polynomial of divides .

    Step 2: The roots of are and . Thus, the eigenvalues of can only be or .

    Step 3: Since is a matrix, it has exactly 3 eigenvalues. Let be the number of eigenvalues equal to , and be the number equal to .

    Step 4: The trace of is the sum of its eigenvalues: .

    Step 5: Solving for : .

    Step 6: The eigenvalues of are and .

    Step 7: The minimum value of on the unit sphere is .

    Answer: 2

    Question 5 · Linear Algebra MCQ

    If the eigenvalues of a symmetric matrix are and , the quadratic form is classified as:

    1. A.

      Positive Definite

    2. B.

      Negative Definite

    3. C.

      Indefinite

    4. D.

      Positive Semi-Definite

    Correct Answer:

    C

    Step-by-Step Solution

    Key idea: This is a classification question based on the signs of eigenvalues.

    Step 1: Recall the classification rules for quadratic forms using eigenvalues ():

    • Positive Definite: All .
    • Negative Definite: All .
    • Indefinite: Some and some .

    Step 2: Examine the given eigenvalues: (positive) and (negative).

    Step 3: Since there is a mix of positive and negative eigenvalues, the form is Indefinite.

    Answer: C

    Question 6 · Linear Algebra MCQ

    A matrix is an orthogonal projection matrix. If the rank of is , what is the sum of its eigenvalues?

    1. A.

      1

    2. B.

      2

    3. C.

      3

    4. D.

      0

    Correct Answer:

    B

    Step-by-Step Solution

    Key idea: The eigenvalues of an orthogonal projection matrix are strictly and .

    Step 1: The rank of a projection matrix equals the number of eigenvalues that are .

    Step 2: Since the rank is , the eigenvalues are and .

    Step 3: The sum of the eigenvalues is the trace of the matrix.

    Step 4: Sum .

    Answer: 2

    Question 7 · Linear Algebra MCQ

    Consider the following statements:

    Assertion (A): The quadratic form with is positive definite.

    Reason (R): The eigenvalues of are both positive.

    Which of the following is correct?

    1. A.

      Both A and R are true and R is the correct explanation of A.

    2. B.

      Both A and R are true but R is NOT the correct explanation of A.

    3. C.

      A is true but R is false.

    4. D.

      A is false but R is true.

    Correct Answer:

    D

    Step-by-Step Solution

    Key idea: Definiteness of a quadratic form is determined by the eigenvalues of its symmetric part, not the original non-symmetric matrix.

    Step 1: Check Reason (R): The eigenvalues of are the roots of , which are and . Both are positive. So R is true.

    Step 2: Check Assertion (A): The symmetric part of is .

    Step 3: The eigenvalues of are and . Since one eigenvalue is , the form is positive semi-definite, not positive definite. So A is false.

    Answer: A is false but R is true.

    Question 8 · Linear Algebra MCQ
    Match the following matrix properties with their correct values for a centering matrix .
    List I: 1. Trace of 2. Determinant of 3. Eigenvalues of
    List II: P. and (with multiplicities and ) Q. R.
    1. A.

      1-P, 2-Q, 3-R

    2. B.

      1-R, 2-Q, 3-P

    3. C.

      1-Q, 2-R, 3-P

    4. D.

      1-R, 2-P, 3-Q

    Correct Answer:

    B

    Step-by-Step Solution

    Key idea: The centering matrix has specific trace, determinant, and eigenvalue properties.

    Step 1: For , the eigenvalues of are (with multiplicity ) and (with multiplicity ). So eigenvalues are and . Matches P.

    Step 2: The trace is the sum of eigenvalues: . Matches R.

    Step 3: The determinant is the product of eigenvalues: . Matches Q.

    Step 4: Correct matching is 1-R, 2-Q, 3-P.

    Answer: 1-R, 2-Q, 3-P

    Question 9 · Linear Algebra MCQ

    Let . If , for how many values of is the expression positive definite for all ?

    1. A.

      1

    2. B.

      2

    3. C.

      3

    4. D.

      4

    Correct Answer:

    C

    Step-by-Step Solution

    Key idea: A symmetric matrix is positive definite if and only if all its leading principal minors are strictly positive.

    Step 1: The first leading principal minor is . For positive definiteness, we need .

    Step 2: The second leading principal minor is the determinant, . We need , which implies or .

    Step 3: Combining and , we get .

    Step 4: Given the set , the values satisfying are and .

    Step 5: There are exactly 3 such values.

    Answer: 3

    Question 10 · Linear Algebra MCQ

    Consider the following statements:

    Assertion (A): The expression with is positive definite.

    Reason (R): The diagonal elements of are positive.

    Which of the following is correct?

    1. A.

      Both A and R are true and R is the correct explanation of A.

    2. B.

      Both A and R are true but R is NOT the correct explanation of A.

    3. C.

      A is true but R is false.

    4. D.

      A is false but R is true.

    Correct Answer:

    D

    Step-by-Step Solution

    Key idea: The definiteness of a quadratic form is determined solely by the eigenvalues of its symmetric part, not the original non-symmetric matrix.

    Step 1: Check Reason (R): The diagonal elements of are and , which are positive. So R is true.

    Step 2: Check Assertion (A): We must symmetrize to find the true matrix governing the quadratic form. The symmetric part is .

    Step 3: The eigenvalues of are found from .

    Step 4: Since one eigenvalue is negative, the expression is indefinite, not positive definite. So A is false.

    Answer: A is false but R is true.

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