Orthogonal, Projection and Special Matrices Notes for GATE DA
Orthogonal, Projection and Special Matrices notes for GATE DA: 18 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice ques
orthogonal projection and special matrices notes
Chapter Roadmap: Orthogonal, Projection and Special Matrices
Chapter Roadmap
Welcome to the geometry of linear transformations. This chapter bridges the gap between abstract matrix algebra and visual geometric intuition.
Your Learning Journey
1. Projection Matrices and Quadratic Forms
Classifying surfaces, Rayleigh quotient, centering matrix. High Weightage
2. Orthogonal and Involutory Matrices
Length-preserving transformations, rotations, own inverses. Moderate Weightage
By the end of this chapter, you will:
Instantly classify the shape of any quadratic form using eigenvalues.
Recognize projection matrices and deduce their eigenvalues without calculation.
Solve constrained optimization problems in seconds.
The Geometry of Quadratic Forms
The Geometry of Quadratic Forms
A quadratic form is a scalar-valued polynomial where every term has a degree of exactly two.
For a column vector x∈Rn and an n×n matrix A, the quadratic form is written as:
Q(x)=xTAx
Geometric Intuition
If you set Q(x)=c for some constant c, you get a geometric surface:
In 2D: Conic sections (ellipses, hyperbolas, parabolas).
In 3D: Quadric surfaces (ellipsoids, hyperboloids).
The matrix A acts as the "DNA" of this surface, dictating its orientation, stretching, and curvature.
The Symmetric Matrix Representation
The Symmetric Matrix Representation
Every quadratic form can be represented by a unique symmetric matrix.
If you are given a non-symmetric matrix B, the quadratic form xTBx is exactly equal to xTAx, where A is the symmetrized version of B:
A=2B+BT
Why does this work?
Because xTBx is a scalar, it equals its own transpose:
xTBx=(xTBx)T=xTBTx
Averaging the two gives the symmetric equivalent.
Golden Rule: Always symmetrize the matrix before analyzing eigenvalues or definiteness.
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Question 1
Level 1: Warm-up
For the centering matrix M=In−n111T, what is the value of M1?
Question 2
Level 1: Warm-up
Let A be a symmetric matrix with eigenvalues 3,3, and 5. What is the minimum value of xTAx subject to xTx=1?
Question 3
Level 1: Warm-up
Let A be a 3×3 real symmetric matrix such that the eigenvalues of A2 are 1,4, and 9. What is the minimum value of xTAx subject to xTx=1?
Question 4
Level 1: Warm-up
Let A be a 3×3 real symmetric matrix such that A2−7A+10I=0. If the trace of A is 12, what is the minimum value of xTAx subject to xTx=1?
Question 5
Level 1: Warm-up
If the eigenvalues of a symmetric matrix A are 2 and −3, the quadratic form xTAx is classified as:
Question 6
Level 1: Warm-up
A 3×3 matrix P is an orthogonal projection matrix. If the rank of P is 2, what is the sum of its eigenvalues?
Question 7
Level 1: Warm-up
Consider the following statements:
Assertion (A): The quadratic form Q(x)=xTBx with B=(1021) is positive definite.
Reason (R): The eigenvalues of B are both positive.
Which of the following is correct?
Question 8
Level 1: Warm-up
Match the following matrix properties with their correct values for a 3×3 centering matrix M=I3−3111T.
List I:
1. Trace of M
2. Determinant of M
3. Eigenvalues of M List II:
P. 0 and 1 (with multiplicities 2 and 1)
Q. 0
R. 2
Question 9
Level 1: Warm-up
Let A=(a22a). If a∈{1,2,3,4,5}, for how many values of a is the expression xTAx positive definite for all x=0?
Question 10
Level 1: Warm-up
Consider the following statements:
Assertion (A): The expression Q(x)=xTBx with B=(2052) is positive definite.
Reason (R): The diagonal elements of B are positive.
Which of the following is correct?
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Orthogonal, Projection and Special Matrices Notes for GATE DA
Orthogonal, Projection and Special Matrices notes for GATE DA: 18 study cards covering concepts, formulas, shortcuts and exam traps, plus solved practice questions.
Chapter Roadmap: Orthogonal, Projection and Special Matrices
Chapter Roadmap
Welcome to the geometry of linear transformations. This chapter bridges the gap between abstract matrix algebra and visual geometric intuition.
Your Learning Journey
1. Projection Matrices and Quadratic Forms
Classifying surfaces, Rayleigh quotient, centering matrix. High Weightage
2. Orthogonal and Involutory Matrices
Length-preserving transformations, rotations, own inverses. Moderate Weightage
By the end of this chapter, you will:
Instantly classify the shape of any quadratic form using eigenvalues.
Recognize projection matrices and deduce their eigenvalues without calculation.
Solve constrained optimization problems in seconds.
The Geometry of Quadratic Forms
The Geometry of Quadratic Forms
A quadratic form is a scalar-valued polynomial where every term has a degree of exactly two.
For a column vector x∈Rn and an n×n matrix A, the quadratic form is written as:
Q(x)=xTAx
Geometric Intuition
If you set Q(x)=c for some constant c, you get a geometric surface:
In 2D: Conic sections (ellipses, hyperbolas, parabolas).
In 3D: Quadric surfaces (ellipsoids, hyperboloids).
The matrix A acts as the "DNA" of this surface, dictating its orientation, stretching, and curvature.
The Symmetric Matrix Representation
The Symmetric Matrix Representation
Every quadratic form can be represented by a unique symmetric matrix.
If you are given a non-symmetric matrix B, the quadratic form xTBx is exactly equal to xTAx, where A is the symmetrized version of B:
A=2B+BT
Why does this work?
Because xTBx is a scalar, it equals its own transpose:
xTBx=(xTBx)T=xTBTx
Averaging the two gives the symmetric equivalent.
Golden Rule: Always symmetrize the matrix before analyzing eigenvalues or definiteness.
Classifying Quadratic Forms
Classifying Quadratic Forms
We classify quadratic forms by observing the sign of Q(x)=xTAx for all non-zero vectors x. This classification depends entirely on the eigenvalues of the symmetric matrix A.
Classification
Eigenvalues of A
Shape (2D)
Positive Definite
All λi>0
Ellipse
Negative Definite
All λi<0
Ellipse (imaginary)
Positive Semi-Definite
All λi≥0
Line or point
Negative Semi-Definite
All λi≤0
Line or point
Indefinite
Mixed signs (+,−)
Hyperbola
Exam Shortcut: To check definiteness, just find the eigenvalues of the symmetrized matrix and check their signs.
Orthogonal, Projection and Special Matrices: Solved Questions with Step-by-Step Explanations (10 Problems)
Question 1 · Linear AlgebraNAT
For the centering matrix M=In−n111T, what is the value of M1?
Correct Answer:
0
Step-by-Step Solution
Key idea: This is a direct substitution question testing the action of the centering matrix on the all-ones vector.
Step 1: Write down the expression for M1:
M1=(In−n111T)1
Step 2: Distribute the vector 1:
M1=In1−n11(1T1)
Step 3: Simplify the terms:
In1=1.
1T1 is the dot product of the all-ones vector with itself, which equals n (the sum of n ones).
Step 4: Substitute back:
M1=1−n11(n)=1−1=0
Step 5: The result is the zero vector. In NAT format asking for "the value" or implying a magnitude/component context where 0 is the unique numeric answer, the answer is 0.
Answer: 0
Question 2 · Linear AlgebraMCQ
Let A be a symmetric matrix with eigenvalues 3,3, and 5. What is the minimum value of xTAx subject to xTx=1?
A.
3
B.
5
C.
9
D.
15
Correct Answer:
A
Step-by-Step Solution
Key idea: The minimum value of a quadratic form xTAx on the unit sphere is the smallest eigenvalue of A.
Step 1: The matrix A is symmetric with eigenvalues 3,3, and 5.
Step 2: By the Rayleigh quotient theorem, the minimum value is λmin.
Step 3: The smallest eigenvalue is 3.
Answer: 3
Question 3 · Linear AlgebraMCQ
Let A be a 3×3 real symmetric matrix such that the eigenvalues of A2 are 1,4, and 9. What is the minimum value of xTAx subject to xTx=1?
A.
-9
B.
-3
C.
1
D.
3
Correct Answer:
B
Step-by-Step Solution
Key idea: The minimum value of a quadratic form on the unit sphere is the smallest eigenvalue of the symmetric matrix.
Step 1: If the eigenvalues of A2 are 1,4,9, then the eigenvalues of A must be ±1,±2,±3.
Step 2: Since A is a real symmetric matrix, its eigenvalues are real. The possible sets of eigenvalues for A are formed by choosing one sign for each magnitude.
Step 3: To find the absolute minimum possible value of the quadratic form, we want the most negative eigenvalue possible for A.
Step 4: The most negative choice is −3. Thus, the minimum value of xTAx is −3.
Answer: -3
Question 4 · Linear AlgebraMCQ
Let A be a 3×3 real symmetric matrix such that A2−7A+10I=0. If the trace of A is 12, what is the minimum value of xTAx subject to xTx=1?
A.
2
B.
5
C.
12
D.
10
Correct Answer:
A
Step-by-Step Solution
Key idea: The minimum value of a quadratic form on the unit sphere is the smallest eigenvalue of the symmetric matrix.
Step 1: The matrix equation A2−7A+10I=0 implies that the minimal polynomial of A divides λ2−7λ+10=0.
Step 2: The roots of λ2−7λ+10=0 are λ=2 and λ=5. Thus, the eigenvalues of A can only be 2 or 5.
Step 3: Since A is a 3×3 matrix, it has exactly 3 eigenvalues. Let k be the number of eigenvalues equal to 5, and 3−k be the number equal to 2.
Step 4: The trace of A is the sum of its eigenvalues: 5k+2(3−k)=12.
Step 5: Solving for k: 5k+6−2k=12⟹3k=6⟹k=2.
Step 6: The eigenvalues of A are 5,5, and 2.
Step 7: The minimum value of xTAx on the unit sphere is λmin=2.
Answer: 2
Question 5 · Linear AlgebraMCQ
If the eigenvalues of a symmetric matrix A are 2 and −3, the quadratic form xTAx is classified as:
A.
Positive Definite
B.
Negative Definite
C.
Indefinite
D.
Positive Semi-Definite
Correct Answer:
C
Step-by-Step Solution
Key idea: This is a classification question based on the signs of eigenvalues.
Step 1: Recall the classification rules for quadratic forms using eigenvalues (λ):
Positive Definite: All λ>0.
Negative Definite: All λ<0.
Indefinite: Some λ>0 and some λ<0.
Step 2: Examine the given eigenvalues: 2 (positive) and −3 (negative).
Step 3: Since there is a mix of positive and negative eigenvalues, the form is Indefinite.
Answer: C
Question 6 · Linear AlgebraMCQ
A 3×3 matrix P is an orthogonal projection matrix. If the rank of P is 2, what is the sum of its eigenvalues?
A.
1
B.
2
C.
3
D.
0
Correct Answer:
B
Step-by-Step Solution
Key idea: The eigenvalues of an orthogonal projection matrix are strictly 0 and 1.
Step 1: The rank of a projection matrix equals the number of eigenvalues that are 1.
Step 2: Since the rank is 2, the eigenvalues are 1,1, and 0.
Step 3: The sum of the eigenvalues is the trace of the matrix.
Step 4: Sum =1+1+0=2.
Answer: 2
Question 7 · Linear AlgebraMCQ
Consider the following statements:
Assertion (A): The quadratic form Q(x)=xTBx with B=(1021) is positive definite.
Reason (R): The eigenvalues of B are both positive.
Which of the following is correct?
A.
Both A and R are true and R is the correct explanation of A.
B.
Both A and R are true but R is NOT the correct explanation of A.
C.
A is true but R is false.
D.
A is false but R is true.
Correct Answer:
D
Step-by-Step Solution
Key idea: Definiteness of a quadratic form is determined by the eigenvalues of its symmetric part, not the original non-symmetric matrix.
Step 1: Check Reason (R): The eigenvalues of B=(1021) are the roots of (1−λ)2=0, which are 1 and 1. Both are positive. So R is true.
Step 2: Check Assertion (A): The symmetric part of B is A=2B+BT=(1111).
Step 3: The eigenvalues of A are 0 and 2. Since one eigenvalue is 0, the form is positive semi-definite, not positive definite. So A is false.
Answer: A is false but R is true.
Question 8 · Linear AlgebraMCQ
Match the following matrix properties with their correct values for a 3×3 centering matrix M=I3−3111T.
List I:
1. Trace of M
2. Determinant of M
3. Eigenvalues of M List II:
P. 0 and 1 (with multiplicities 2 and 1)
Q. 0
R. 2
A.
1-P, 2-Q, 3-R
B.
1-R, 2-Q, 3-P
C.
1-Q, 2-R, 3-P
D.
1-R, 2-P, 3-Q
Correct Answer:
B
Step-by-Step Solution
Key idea: The centering matrix M=In−n111T has specific trace, determinant, and eigenvalue properties.
Step 1: For n=3, the eigenvalues of M are 1 (with multiplicity n−1=2) and 0 (with multiplicity 1). So eigenvalues are 0 and 1. Matches P.
Step 2: The trace is the sum of eigenvalues: 1+1+0=2. Matches R.
Step 3: The determinant is the product of eigenvalues: 1×1×0=0. Matches Q.
Step 4: Correct matching is 1-R, 2-Q, 3-P.
Answer: 1-R, 2-Q, 3-P
Question 9 · Linear AlgebraMCQ
Let A=(a22a). If a∈{1,2,3,4,5}, for how many values of a is the expression xTAx positive definite for all x=0?
A.
1
B.
2
C.
3
D.
4
Correct Answer:
C
Step-by-Step Solution
Key idea: A symmetric matrix is positive definite if and only if all its leading principal minors are strictly positive.
Step 1: The first leading principal minor is a. For positive definiteness, we need a>0.
Step 2: The second leading principal minor is the determinant, det(A)=a2−4. We need a2−4>0, which implies a>2 or a<−2.
Step 3: Combining a>0 and a>2, we get a>2.
Step 4: Given the set a∈{1,2,3,4,5}, the values satisfying a>2 are 3,4, and 5.
Step 5: There are exactly 3 such values.
Answer: 3
Question 10 · Linear AlgebraMCQ
Consider the following statements:
Assertion (A): The expression Q(x)=xTBx with B=(2052) is positive definite.
Reason (R): The diagonal elements of B are positive.
Which of the following is correct?
A.
Both A and R are true and R is the correct explanation of A.
B.
Both A and R are true but R is NOT the correct explanation of A.
C.
A is true but R is false.
D.
A is false but R is true.
Correct Answer:
D
Step-by-Step Solution
Key idea: The definiteness of a quadratic form is determined solely by the eigenvalues of its symmetric part, not the original non-symmetric matrix.
Step 1: Check Reason (R): The diagonal elements of B are 2 and 2, which are positive. So R is true.
Step 2: Check Assertion (A): We must symmetrize B to find the true matrix governing the quadratic form. The symmetric part is A=2B+BT=(22.52.52).
Step 3: The eigenvalues of A are found from (2−λ)2−2.52=0⟹2−λ=±2.5⟹λ=4.5,−0.5.
Step 4: Since one eigenvalue is negative, the expression is indefinite, not positive definite. So A is false.