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    Vector Spaces PYQs for GATE DA

    GATE DA Vector Spaces: 5 chapters, 5 previous year questions (25% of Linear Algebra), 266 practice questions and one solved question from each chapter.

    A question from this chapter

    Question 1
    2026 PYQ
    Level 3: Exam Standard
    Consider a set . Let be another set which is a subspace of with dimension two.
    Which of the following gives the area of ?
    Question 2
    2024 PYQ
    Level 3: Exam Standard
    Which of the following statements is/are TRUE?
    Note: denotes the set of real numbers.
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    Vector Spaces PYQs for GATE DA

    GATE DA Vector Spaces: 5 chapters, 5 previous year questions (25% of Linear Algebra), 266 practice questions and one solved question from each chapter.

    About Vector Spaces Previous Year Questions (PYQs)

    5 previous year questions from Vector Spaces in GATE DA, grouped by chapter with the exam year, answer key and step-by-step solution for each.

    Vector Spaces Weightage in GATE DA

    Vector Spaces accounts for 5 of 20 Linear Algebra previous year questions in our bank (25%), about 1.7 per paper across 3 papers.

    Vector Spaces Chapter Matrix

    ChapterTopicsPYQsShare of unit PYQsPractice questions
    Chapter 1 — Vector Spaces00%0
    Vector Spaces, Subspaces and BasesSubspaces, Linear Independence and Orthonormal Bases, Geometry of Subspaces and Norm Balls360%154
    Chapter 2 — Vector Spaces00%0
    Orthogonality, Projections and Linear SystemsProjection Matrices, Null Space and Idempotence, Consistency and Solution Sets of Linear Systems240%112
    Chapter 3 — Vector Spaces00%0

    More from Linear Algebra

    One Solved Question from Each Vector Spaces Chapter

    Question 1 · Vector Spaces, Subspaces and Bases · 2026 MCQ
    Consider a set . Let be another set which is a subspace of with dimension two.
    Which of the following gives the area of ?
    1. A.

    2. B.

    3. C.

    4. D.

    Correct Answer:

    A

    Step-by-Step Solution

    Insight: The intersection of a solid n-dimensional ball with a k-dimensional subspace passing through the origin is a solid k-dimensional ball of the exact same radius.

    Exam route: means , so it's a solid 3D ball of radius . is a 2D subspace (a plane through the origin). The intersection is a 2D solid disk of radius 4. Area = .

    Learning route:

    1. Identify : The condition is equivalent to , which means . This defines a solid 3-dimensional ball centered at the origin with radius .
    2. Identify : A subspace of with dimension 2 is a flat plane that passes exactly through the origin.
    3. Find the intersection : Slicing a solid 3D sphere with a plane that passes through its exact center (the origin) yields a solid 2D disk (a "great disk") with the same radius .
    4. Calculate the area: The area of a 2D disk of radius is . Substituting , we get Area = .
    Question 2 · Orthogonality, Projections and Linear Systems · 2024 MSQ
    Which of the following statements is/are TRUE?
    Note: denotes the set of real numbers.
    1. A. There exist , , and such that has a unique
      solution and has infinite solutions.
    2. B. There exist , , and such that has no solutions
      and has infinite solutions.
    3. C. There exist , , and such that has a unique
      solution and has infinite solutions.
    4. D. There exist , , and such that has a unique
      solution and has no solutions.
    Correct Answer:

    ["B","D"]

    Step-by-Step Solution

    Key idea: This question tests the consistency conditions of linear systems based on the shape of matrix (square, wide, or tall) and its rank.

    Step 1: Analyze Option A ().

    For a square matrix , if has a unique solution, then ( is invertible).

    If is invertible, must also have a unique solution () for ANY .

    It is impossible for an invertible matrix to have infinite solutions for any RHS.

    Thus, Option A is FALSE.

    Step 2: Analyze Option B ().

    Can have no solution and have infinite solutions?

    Yes. Let be singular (Rank < 3).

    Example: .

    • Let . System is inconsistent (no solution) because .
    • Let . System is . is free. Infinite solutions.

    Thus, Option B is TRUE.

    Step 3: Analyze Option C ().

    Can have a unique solution?

    has 3 columns (variables) and 2 rows (equations).

    Max Rank is 2.

    Number of free variables = .

    If a solution exists, there is at least 1 free variable, implying infinite solutions.

    A unique solution is impossible for a wide matrix ().

    Thus, Option C is FALSE.

    Step 4: Analyze Option D ().

    Can have a unique solution?

    has 2 columns. Max Rank is 2.

    If Rank()=2, the columns are linearly independent.

    If is in the column space, the solution is unique (0 free variables).

    Can have no solution?

    Yes, if is not in the column space (which is a 2D plane in ).

    So, Unique Solution AND No Solution are both possible for different RHS vectors.

    Thus, Option D is TRUE.

    Answer: Options B and D are TRUE.